4/9x^4-1/3x^2y+1/16y^2=0

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Solution for 4/9x^4-1/3x^2y+1/16y^2=0 equation: 


x in (-oo:+oo)

(4/9)*x^4-((1/3)*x^2*y)+(1/16)*y^2 = 0

(4/9)*x^4+(-1/3)*x^2*y+(1/16)*y^2 = 0

4/9*x^4-1/3*x^2*y+1/16*y^2 = 0

t_1 = x^2

4/9*t_1^2-1/3*t_1^1*y+1/16*y^2 = 0

4/9*t_1^2-1/3*t_1*y+1/16*y^2 = 0

DELTA = (-1/3*y)^2-(1/16*4/9*4*y^2)

DELTA = 0

t_1 = (-(-1/3*y))/(4/9*2)

t_1 = 3/8*y or t_1 = 3/8*y

t_1 = 3/8*y

x^2-(3/8*y) = 0

x^2-3/8*y = 0

1*x^2 = -(-3/8*y) // : 1

x^2 = 3/8*y

x^2 = 3/8*y // ^ 1/2

abs(x) = (3/8)^(1/2)*y^(1/2)

x = (3/8)^(1/2)*y^(1/2) or x = -((3/8)^(1/2)*y^(1/2))

t_1 = 3/8*y

x^2-(3/8*y) = 0

x^2-3/8*y = 0

1*x^2 = -(-3/8*y) // : 1

x^2 = 3/8*y

x^2 = 3/8*y // ^ 1/2

abs(x) = (3/8)^(1/2)*y^(1/2)

x = (3/8)^(1/2)*y^(1/2) or x = -((3/8)^(1/2)*y^(1/2))

x in { (3/8)^(1/2)*y^(1/2), -((3/8)^(1/2)*y^(1/2)), (3/8)^(1/2)*y^(1/2), -((3/8)^(1/2)*y^(1/2)) }

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